5[4-2(a-2)]=5(2-4a)

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Solution for 5[4-2(a-2)]=5(2-4a) equation:


Simplifying
5[4 + -2(a + -2)] = 5(2 + -4a)

Reorder the terms:
5[4 + -2(-2 + a)] = 5(2 + -4a)
5[4 + (-2 * -2 + a * -2)] = 5(2 + -4a)
5[4 + (4 + -2a)] = 5(2 + -4a)

Combine like terms: 4 + 4 = 8
5[8 + -2a] = 5(2 + -4a)
[8 * 5 + -2a * 5] = 5(2 + -4a)
[40 + -10a] = 5(2 + -4a)
40 + -10a = (2 * 5 + -4a * 5)
40 + -10a = (10 + -20a)

Solving
40 + -10a = 10 + -20a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '20a' to each side of the equation.
40 + -10a + 20a = 10 + -20a + 20a

Combine like terms: -10a + 20a = 10a
40 + 10a = 10 + -20a + 20a

Combine like terms: -20a + 20a = 0
40 + 10a = 10 + 0
40 + 10a = 10

Add '-40' to each side of the equation.
40 + -40 + 10a = 10 + -40

Combine like terms: 40 + -40 = 0
0 + 10a = 10 + -40
10a = 10 + -40

Combine like terms: 10 + -40 = -30
10a = -30

Divide each side by '10'.
a = -3

Simplifying
a = -3

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